just for fun i broke out the 7th grade Trig and calculated the diameter of the target area, at 25 yards, seen by two apertures, .125" (original) and .170’’ (enlarged)
8.01 ft = .125"
11.25 ft= .170"
(give or take as i used 14" as the distance between front and rear sights, so not measured, just guessed)
so a difference of 3ft, if my math is correct
just for fun